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MMI:eV:MI:aV:QqBAjp=jBAJr=jBAjs=jCAjt=jDAju?MkI:qnu=JIAjt=jIWx:>n;J^>JLwm;Fn;nm;vMqV:uV:kV:uV:eV:uV:aV:yV:]V:=W:]V:CW:]V :IW:aV:MW:enOAJFAJPAjGAjOAJIAjNwm;vN;W:COZ:>:::::::::::::::: ::::4:" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 28 "Zad\341n\355 obvodu pod le obr\341zku." }{MPLTEXT 1 0 0 "" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 73 "Obvod:= \"zesilova\350\nV1 1 0\nR0 1 2\nR1 2 4\nG1 3 4 2 4 S\nR2 4 0\nRz 3 0\n.end\":" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 150 "V\375po \350et uzlov\375ch nap\354t\355 a proud\371 v\354tv\355 obvodu. V\375p o\350et nap\354\235ov\351ho p\370enosu symbolicky i \350\355seln\354 ( m\355sto funkce pro v\375b\354r lze samoz\370ejm\354 pou\236\355t i p \370\355kaz " }{TEXT 257 6 "assign" }{TEXT -1 27 " pro glob\341ln\355 \+ p\370i\370azen\355). " }{MPLTEXT 1 0 0 "" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 131 "napeti:=syrup(Obvod, ac, 'proudy'):\np:=simplify(sub s(napeti,v[3]/v[1]));\npn:=evalf(subs(\{R0=50,R1=2500,R2=1000,Rz=5000, S=0.04\},p));" }}{PARA 6 "" 1 "" {TEXT -1 66 "parsedeck: Analyzing S PICE deck \"zesilova\350\" (ignoring this line)" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"pG,$**%#RzG\"\"\"%\"SGF(%#R1GF(,*F*F(%#R2GF(%#R0GF( *(F)F(F*F(F,F(F(!\"\"F/" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#pnG$!+D_ eG[!\"*" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 176 "Ur\350en\355 jednotli v\375ch p\370enosov\375ch koeficient\371 a v\375po\350et nap\354\235ov \351ho p\370enosu s jejich pou\236it\355m a ov\354\370en\355 spr\341vn osti v\375po\350tu SYRUPem. Vy\350\355slen\355 vratn\351ho roz\355lu a nap\354\235ov\351ho p\370enosu." }{MPLTEXT 1 0 1 " " }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 154 "Rp:=R2*(R1+R0)/(R0+R1+R2):\nK1:=(R1)/(R0+R1+R2) :\nK:=S:\nK2:=-Rz:\nK4:=-R1*Rp/(R1+R0):\nF:=1-K4*K;\nFn:=evalf(subs(\{ R0=50,R1=2500,R2=1000,Rz=5000,S=0.04\},F)); \n" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"FG,&\"\"\"F&**%#R1GF&%#R2GF&,(%#R0GF&F)F&F(F&!\"\"% \"SGF&F&" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#FnG$\"+39!p\"H!\")" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 102 "pk:=simplify(K1*K2*K/F);\ns implify(p-pk);\npkn:=evalf(subs(\{R0=50,R1=2500,R2=1000,Rz=5000,S=0.04 \},pk)); " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#pkG,$**%#RzG\"\"\"%\"S GF(%#R1GF(,*F*F(%#R2GF(%#R0GF(*(F)F(F*F(F,F(F(!\"\"F/" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#\"\"!" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$pknG$! +D_eG[!\"*" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 107 "V\375po\350et vstu pn\355ho odporu bez vlivu ZV a s jej\355m vlivem. Vstupn\355 odpor je \+ v tomto p\370\355pad\354 ch\341p\341n bez odporu " }{XPPEDIT 18 0 "R0; " "6#%#R0G" }{TEXT -1 69 ", proto je nutn\351 ho v tomto p\370\355pad \354 vynulovat (je seriov\354 s odporem " }{XPPEDIT 18 0 "R1;" "6#%#R 1G" }{TEXT -1 3 "). " }{MPLTEXT 1 0 0 "" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 16 "Rvst_bez:=R1+R2;" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 39 "Rvst_:= simplify(Rvst_bez*subs(R0=0,F));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>% )Rvst_bezG,&%#R2G\"\"\"%#R1GF'" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&R vst_G,(%#R2G\"\"\"*(%\"SGF'%#R1GF'F&F'F'F*F'" }}}{EXCHG {PARA 0 "" 0 " " {TEXT -1 97 "Je mo\236n\351 si zkontrolovat i zes\355len\355 bez vli vu ZV. V\375sledek je v takto jednoduch\351m p\370\355pad\354 z\370ejm \375." }{MPLTEXT 1 0 0 "" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 26 "pk_bez: =simplify(K1*K2*K);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%'pk_bezG,$**% #R1G\"\"\",(%#R0GF(%#R2GF(F'F(!\"\"%#RzGF(%\"SGF(F," }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 64 "Ov\354\370en\355 vztahu pro vstupn\355 odpor po moc\355 SYRUPu a jeho vy\350\355slen\355." }{MPLTEXT 1 0 1 " " }} {PARA 0 "> " 0 "" {MPLTEXT 1 0 47 "Rvst:=simplify(subs(napeti,proudy,v [2]/i[R0]));" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 65 "Rvstn:=evalf(subs( \{R0=50,R1=2500,R2=1000,Rz=5000,S=0.04\},Rvst)); " }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%RvstG,(%#R2G\"\"\"*(%\"SGF'%#R1GF'F&F'F'F*F'" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%&RvstnG$\")++N5!\"#" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{MARK "1 0 0" 8 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }